64x^2+53x+9=5x

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Solution for 64x^2+53x+9=5x equation: 



64x^2+53x+9=5x

We move all terms to the left:

64x^2+53x+9-(5x)=0

We add all the numbers together, and all the variables

64x^2+48x+9=0

a = 64; b = 48; c = +9;
Δ = b2-4ac
Δ = 482-4·64·9
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-48}{128}=-3/8$

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